Free Essays on Mythology Short Story

For ages man has looked up at the Moon with wonder in his mind. Why does the Moon exist? Why hasn’t the Moon come crashing into the Earth and destroyed us all? While these questions have been answered by modern ideals and science, I will tell you the real reason the Moon exists. Long ago when the world was just spec of dust in the universe, and life had not found its way to the planet, a great struggle occurred between the two most powerful gods, Sunubious and his smaller brother Moonous. Sunubious was the creator of the world, and between the two of the planned to rule over all life for all time. Sunubious had started the creation by creating powerful immortals to form the Earth. He shot down powerful flames of all colors to help him make the Earth. These colors turned into several lesser gods. The blue flame was responsible for creating great oceans, seas, lakes, rivers, ponds and all the life that would reside in them. The red flame had to create the rock and lava that made up the surface of the Earth. Next, he sent down the green flame or Natures flame. She began to make trees and other vegetation grow from the earth. She also formed all the different landscapes that make the different ecosystems on the earth. Sunubious had ordered her to make t he entire world the same, but she openly defied the great god. Before Sunubious could send down the white flame, the flame of creation, he had to decide where to create life. His original plan was to have all kinds of life all over the world, but since natures flame had defied him, he was stuck in an awkward position. He consulted his younger brother Moonous, who had not grown his mighty flames and was thus still a young god. Moonous was very clever and not the most trustworthy of siblings. When Sunubious asked for his help he quickly agreed. Moonous told Sunubious that life could be created anywhere, since he was such a powerful god any life he creates will be able to ... Free Essays on Mythology Short Story Free Essays on Mythology Short Story For ages man has looked up at the Moon with wonder in his mind. Why does the Moon exist? Why hasn’t the Moon come crashing into the Earth and destroyed us all? While these questions have been answered by modern ideals and science, I will tell you the real reason the Moon exists. Long ago when the world was just spec of dust in the universe, and life had not found its way to the planet, a great struggle occurred between the two most powerful gods, Sunubious and his smaller brother Moonous. Sunubious was the creator of the world, and between the two of the planned to rule over all life for all time. Sunubious had started the creation by creating powerful immortals to form the Earth. He shot down powerful flames of all colors to help him make the Earth. These colors turned into several lesser gods. The blue flame was responsible for creating great oceans, seas, lakes, rivers, ponds and all the life that would reside in them. The red flame had to create the rock and lava that made up the surface of the Earth. Next, he sent down the green flame or Natures flame. She began to make trees and other vegetation grow from the earth. She also formed all the different landscapes that make the different ecosystems on the earth. Sunubious had ordered her to make t he entire world the same, but she openly defied the great god. Before Sunubious could send down the white flame, the flame of creation, he had to decide where to create life. His original plan was to have all kinds of life all over the world, but since natures flame had defied him, he was stuck in an awkward position. He consulted his younger brother Moonous, who had not grown his mighty flames and was thus still a young god. Moonous was very clever and not the most trustworthy of siblings. When Sunubious asked for his help he quickly agreed. Moonous told Sunubious that life could be created anywhere, since he was such a powerful god any life he creates will be able to ...

Probability of Union of 3 or More Sets

Probability of Union of 3 or More Sets When two events are mutually exclusive, the probability of their union can be calculated with the addition rule. We know that for rolling a die, rolling a number greater than four or a number less than three are mutually exclusive events, with nothing in common. So to find the probability of this event, we simply add the probability that we roll a number greater than four to the probability that we roll a number less than three. In symbols, we have the following, where the capital P  denotes â€Å"probability of†: P(greater than four or less than three) P(greater than four) P(less than three) 2/6 2/6 4/6. If the events are not mutually exclusive, then we do not simply add the probabilities of the events together, but we need to subtract the probability of the intersection of the events. Given the events A and B: P(A U B) P(A) P(B) - P(A ∠© B). Here we account for the possibility of double-counting those elements that are in both A and B, and that is why we subtract the probability of the intersection. The question that arises from this is, â€Å"Why stop with two sets? What is the probability of the union of more than two sets?† Formula for Union of 3 Sets We will extend the above ideas to the situation where we have three sets, which we will denote A, B, and C. We will not assume anything more than this, so there is the possibility that the sets have a non-empty intersection. The goal will be to calculate the probability of the union of these three sets, or P (A U B U C). The above discussion for two sets still holds. We can add together the probabilities of the individual sets A, B, and C, but in doing this we have double-counted some elements. The elements in the intersection of A and B have been double counted as before, but now there are other elements that have potentially been counted twice. The elements in the intersection of A and C and in the intersection of B and C have now also been counted twice. So the probabilities of these intersections must also be subtracted. But have we subtracted too much? There is something new to consider that we did not have to be concerned about when there were only two sets. Just as any two sets can have an intersection, all three sets can also have an intersection. In trying to make sure that we did not double count anything, we have not counted at all those elements that show up in all three sets. So the probability of the intersection of all three sets must be added back in. Here is the formula that is derived from the above discussion: P (A U B U C) P(A) P(B) P(C) - P(A ∠© B) - P(A ∠© C) - P(B ∠© C) P(A ∠© B ∠© C) Example Involving 2 Dice To see the formula for the probability of the union of three sets, suppose we are playing a board game that involves rolling two dice. Due to the rules of the game, we need to get at least one of the die to be a two, three or four to win. What is the probability of this? We note that we are trying to calculate the probability of the union of three events: rolling at least one two, rolling at least one three, rolling at least one four. So we can use the above formula with the following probabilities: The probability of rolling a two is 11/36. The numerator here comes from the fact that there are six outcomes in which the first die is a two, six in which the second die is a two, and one outcome where both dice are twos. This gives us 6 6 - 1 11.The probability of rolling a three is 11/36, for the same reason as above.The probability of rolling a four is 11/36, for the same reason as above.The probability of rolling a two and a three is 2/36. Here we can simply list the possibilities, the two could come first or it could come second.The probability of rolling a two and a four is 2/36, for the same reason that probability of a two and a three is 2/36.The probability of rolling a two, three and a four is 0 because we are only rolling two dice and there is no way to get three numbers with two dice. We now use the formula and see that the probability of getting at least a two, a three or a four is 11/36 11/36 11/36 – 2/36 – 2/36 – 2/36 0 27/36. Formula for Probability of Union of 4 Sets The reason why the formula for the probability of the union of four sets has its form is similar to the reasoning for the formula for three sets. As the number of sets increases, the number of pairs, triples and so on increase as well. With four sets there are six pairwise intersections that must be subtracted, four triple intersections to add back in, and now a quadruple intersection that needs to be subtracted. Given four sets A, B, C and D, the formula for the union of these sets is as follows: P (A U B U C U D) P(A) P(B) P(C) P(D) - P(A ∠© B) - P(A ∠© C) - P(A ∠© D)- P(B ∠© C) - P(B ∠© D) - P(C ∠© D) P(A ∠© B ∠© C) P(A ∠© B ∠© D) P(A ∠© C ∠© D) P(B ∠© C ∠© D) - P(A ∠© B ∠© C ∠© D). Overall Pattern We could write formulas (that would look even scarier than the one above) for the probability of the union of more than four sets, but from studying the above formulas we should notice some patterns. These patterns hold to calculate unions of more than four sets. The probability of the union of any number of sets can be found as follows: Add the probabilities of the individual events.Subtract the probabilities of the intersections of every pair of events.Add the probabilities of the intersection of every set of three events.Subtract the probabilities of the intersection of every set of four events.Continue this process until the last probability is the probability of the intersection of the total number of sets that we started with.